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Answer :
Given,
In \(\triangle PQO\), DE || OQ
So by using Basic Proportionality Theorem,
\(\frac{PD}{DO} = \frac{PE}{EQ}\) ………………. (i)
Again given, in \(\triangle PQO\), DE || OQ ,
So by using Basic Proportionality Theorem,
\(\frac{PD}{DO} = \frac{PF}{FR}\) ………………… (ii)
From equation (i) and (ii), we get,
\(\frac{PE}{EQ} = \frac{PF}{FR}\)
Therefore, by converse of Basic Proportionality Theorem,
EF || QR, in \(\triangle PQR\).