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Answer :
Given here,
In \(\triangle OPQ\), AB || PQ
By using Basic Proportionality Theorem,
\(\frac{OA}{AP} = \frac{OB}{BQ}\)…………….(i)
Also given,
In \(\triangle OPR\), AC || PR
By using Basic Proportionality Theorem
\(\frac{OA}{AP} = \frac{OC}{CR}\)……………(ii)
From equation (i) and (ii), we get,
\(\frac{OB}{BQ} = \frac{OC}{CR}\)
Therefore, by converse of Basic Proportionality Theorem,
In \(\triangle OQR\), BC || QR.