Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
In \(\triangle\)DOC and \(\triangle\)BOA,
AB || CD, thus alternate interior angles will be equal,
\(\angle\)CDO = \(\angle\)ABO
Similarly,
\(\angle\)DCO = \(\angle\)BAO
Also, for the two triangles \(\triangle\)DOC and \(\triangle\)BOA, vertically opposite angles will be equal;
\(\angle\)DOC = \(\angle\)BOA
Hence, by AAA similarity criterion,
\(\triangle\)DOC ~ \(\triangle\)BOA
Thus, the corresponding sides are proportional.
DO/BO = OC/OA
OA/OC = OB/OD
Hence, proved.