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For fig. (a) | For fig. (b) |
---|---|

i) y = x | (i) y = x + 2 |

ii)x + y = 0 | y = x - 2 |

iii)y = 2x | y = -x + 2 |

iv)2 + 3y = 7x | iv)x + 2y = 6 |

Answer :

In fig. (a), we can observe that the points(1, -1) and (-1, 1) lies on the line of equation x + y = 0.

Because, for (-1, 1), (1) + (-1) = 0

and for (1, -1), (-1) + (1) = 0

Similarly, in fig. (b), we can observe that the points(2, 0),(0, 2) and (-1, 3) lies on the line of equation x + y = 2.

Because, for (2, 0), (2) + (0) = 2,

for(0, 2), (0) + (2) = 2

And for (-1, 3), (-1) + (3) = 2

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