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From the choices given below, choose the equation whose graphs are given in fig. (a) and fig. (b).
For fig. (a)For fig. (b)
i) y = x (i) y = x + 2
ii)x + y = 0y = x - 2
iii)y = 2xy = -x + 2
iv)2 + 3y = 7xiv)x + 2y = 6


Answer :

In fig. (a), we can observe that the points(1, -1) and (-1, 1) lies on the line of equation x + y = 0.

Because, for (-1, 1), (1) + (-1) = 0

and for (1, -1), (-1) + (1) = 0


Similarly, in fig. (b), we can observe that the points(2, 0),(0, 2) and (-1, 3) lies on the line of equation x + y = 2.

Because, for (2, 0), (2) + (0) = 2,

for(0, 2), (0) + (2) = 2

And for (-1, 3), (-1) + (3) = 2

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