Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Say \(\triangle\) ABC and \(\triangle\) PQR are two similar triangles and equal in area
Now let us prove \(\triangle\) ABC \({\displaystyle \cong }\) \(\triangle\) PQR.
Since, \(\triangle\) ABC ~ \(\triangle\) PQR
\(\frac{Area of ( \triangle ABC)}{Area of (\triangle PQR)} \) = \(\frac{BC^2}{QR^2} \)
\(\frac{BC^2}{QR^2} \) = 1
[Since, Area(\(\triangle\) ABC) = (\(\triangle\) PQR)
\( BC^2=QR^2 \)
BC = QR
Similarly, we can prove that
AB = PQ and AC = PR