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Answer :

Say \(\triangle\) ABC and \(\triangle\) PQR are two similar triangles and equal in area

Now let us prove \(\triangle\) ABC \({\displaystyle \cong }\) \(\triangle\) PQR.

Since, \(\triangle\) ABC ~ \(\triangle\) PQR

\(\frac{Area of ( \triangle ABC)}{Area of (\triangle PQR)} \) = \(\frac{BC^2}{QR^2} \)

\(\frac{BC^2}{QR^2} \) = 1

[Since, Area(\(\triangle\) ABC) = (\(\triangle\) PQR)

\( BC^2=QR^2 \)

BC = QR

Similarly, we can prove that

AB = PQ and AC = PR

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