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# A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

Given, a guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end.

Let AB be the pole and AC be the wire.

By Pythagoras theorem,

$$AC^2 = AB^2 + BC^2$$
$$24^2 = 18^2 + BC^2$$
$$BC^2 = 576 – 324$$
$$BC^2 = 252$$
$$BC = 6 \sqrt{7}$$m

Therefore, the distance from the base is $$6 \sqrt{7}$$ m