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# Tick the correct answer and justify: In $$\triangle$$ ABC, AB = $$6 \sqrt {3}$$ cm, AC = 12 cm and BC = 6 cm. The angle B is: (A) 120° (B) 60° (C) 90° (D) 45°

Given, in $$\triangle$$ ABC, AB = $$6 \sqrt {3}$$ cm, AC = 12 cm and BC = 6 cm.

We can observe that,
$$AB^2 = 108$$
$$AC^2 = 144$$
And,$$BC^2 = 36$$
$$AB^2 + BC^2 = AC^2$$

The given triangle, $$\triangle$$ ABC, is satisfying Pythagoras theorem.

Therefore, the triangle is a right triangle, right-angled at B.
$$\angle$$ B = 90°

Hence, the correct answer is (C).