Tick the correct answer and justify: In \(\triangle\) ABC, AB = \(6 \sqrt {3}\) cm, AC = 12 cm and BC = 6 cm.
The angle B is:
(A) 120°
(B) 60°
(C) 90°
(D) 45°

Given, in \(\triangle\) ABC, AB = \(6 \sqrt {3}\) cm, AC = 12 cm and BC = 6 cm.


We can observe that,
\(AB^2 = 108\)
\(AC^2 = 144\)
And,\( BC^2 = 36\)
\(AB^2 + BC^2 = AC^2\)

The given triangle, \(\triangle\) ABC, is satisfying Pythagoras theorem.

Therefore, the triangle is a right triangle, right-angled at B.
\(\angle\) B = 90°

Hence, the correct answer is (C).