Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Given, a farmer covers 40 m in 40 s .
So, he will cover 1 m in \( 40 \over 40 \) \( = 1 s \)
Now, after 2 min 20 s which is equal to 140 s , he would have covered \( 140 \over 1 \) \( = 140 m \)
Case 1: When the farmer starts moving from corner of the field
Then, after 140 s he would have covered \( 140 \over 40 \) \( = 3.5 \) rounds of the field.
So, displacement would have been, \( \sqrt{10^2 + 10^2} = 14.1 \ m \) { By Pythagoras theorem}
Case 2: When the farmer starts moving from middle of any side
Then, after 140 s he will be at the middle of the opposite side of his starting side
So, his displacement will be 10 m.
Case 3: When the farmer starts moving from any random point.
Then his displacement will be in between 10 m and 14.1 m