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Answer :
Given, initial speed of bus(u) = 80 km h–1 \( = 80 × \) \( 5 \over 18 \) \( = 22.22 \) m/s
final speed of bus(v) = 60 km h–1 \( = 60 × \) \( 5 \over 18 \) \( = 16.66 \) m/s
Time taken = 5 s
We know that,
a = \( v - u \over t \)
= \( 16.66 - 22.22 \over 5 \)
= \( - 1.112 \ m/s^2 \)
\(\therefore a = - 1.112 \ m/s^2 \)
The negative sign indicates that the bus is actually not accelerating but retarding.