A bus starting from rest moves with a uniform acceleration of 0.1 m s^-2 for 2 minutes. Find
(a) the speed acquired,
(b) the distance travelled.

Given, bus starts from rest, so its initial speed = 0 m/s
a = 0.1 m s^-2

t = 2 min = 120 s

(a) Now,
\(\because \) a = \( v-u \over t \)
\( \Rightarrow v = at + u \)
\( \Rightarrow v = 0.1 × 120 + 0 \)

\(\therefore \) speed acquired \( = \ 12 \ m/s \)

(b) We know that, \( v^2 - u^2 = 2as \)

\(\therefore 12^2 - 0^2 = 2 × 0.1 × s \)
\(\Rightarrow s = \) \( 144 \over 0.2 \)

\(\therefore \) distance travelled = 720 m