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Answer :
Given, the trolley starts from rest. so its initial velocity = 0 m/s
a = \( 2 \ cm /s^2 \) = \( 0.02 \ m/s^2 \)
t= 3 s
By the first motion equation,
\(\therefore v \ = \ u \ + \ at \)
\( \Rightarrow v = 0 + (0.02 × 3 ) \)
\( \Rightarrow v = 0.06 \ m/s^2 \)
Therefore, the velocity of the trolley after 3 seconds will be \( 0.06 \ m/s^2 \)