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# A trolley, while going down an inclined plane, has an acceleration of $$2 \ cm /s^2$$ . What will be its velocity 3 s after the start?

Given, the trolley starts from rest. so its initial velocity = 0 m/s
a = $$2 \ cm /s^2$$ = $$0.02 \ m/s^2$$

t= 3 s

By the first motion equation,

$$\therefore v \ = \ u \ + \ at$$
$$\Rightarrow v = 0 + (0.02 × 3 )$$
$$\Rightarrow v = 0.06 \ m/s^2$$

Therefore, the velocity of the trolley after 3 seconds will be $$0.06 \ m/s^2$$