A trolley, while going down an inclined plane, has an acceleration of \( 2 \ cm /s^2 \) . What will be its velocity 3 s after the start?

Given, the trolley starts from rest. so its initial velocity = 0 m/s
a = \( 2 \ cm /s^2 \) = \( 0.02 \ m/s^2 \)

t= 3 s

By the first motion equation,

\(\therefore v \ = \ u \ + \ at \)
\( \Rightarrow v = 0 + (0.02 × 3 ) \)
\( \Rightarrow v = 0.06 \ m/s^2 \)

Therefore, the velocity of the trolley after 3 seconds will be \( 0.06 \ m/s^2 \)