An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?

Given, dia. of circular track = 200 m
So, circumference
= \( \pi × d \ = \ 3.14 × 200 \ = \ 628 m \)

So, the athlete completes 628 m in 40 s

Then, 1 s in \( 628 \over 40 \) \( = 15.7 m \)

Now, after 2 min 20 sec that is 140 s he would have covered \( 15.7 × 140 \ = \ 2198 m \)

So, he would by 140 sec he would have covered \( 140 \over 40 \) \( =3.5 \) rounds

So, displacement will be equal to dia. of the circular track , i.e., 200 m

Hence, the net distance covered by the athlete is 2198 meters and the total displacement of the athlete is 200 m.