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Answer :
The total displacement of each car can be obtained by calculating the area beneath the speed-time graph.
Therefore, displacement of the first car = area of triangle AOB = \(\frac{1}{2} \) × (OB) × (OA)
But OB = 5 seconds and OA = 52 km/h = 14.44 m/s
Therefore, the area of the triangle AOB is given by: \(\frac{1}{2} \) × (5s) × (14.44m/s) = 36 meters
Now, the displacement of the second car is given by the area of the triangle COD = \(\frac{1}{2} \) × (OD) × (OC)
But OC = 10 seconds and OC = 3km/h = 0.83 m/s
Therefore, area of triangle COD = \(\frac{1}{2} \) × (10s) × (0.83m/s) = 4.15 meters
Therefore, the first car is displaced by 36 meters whereas the second car is displaced by 4.15 meters. Therefore, the first car travelled farther post the application of brakes.