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Answer :
(a) since the slope of line B is the greatest, B is travelling at the fastest speed.
(b) since the three lines do not intersect at a single point, the three objects never meet at the same point on the road.
(c) since there are 7 unit areas of the graph between 0 and 4 on the Y axis, 1 graph unit equals 4/7 km.
Since the initial point of object C is 4 graph units away from the origin, Its initial distance from the origin is 4× \(\frac{4}{7} \) km = \(\frac{16}{7} \) km
When A passes B, the distance between the origin and C is 8 km
Therefore, total distance travelled by C in this time = 8 – \(\frac{16}{7} \) km = 5.71 km
(d) the distance that object B has covered at the point where it passes C is equal to 9 graph units.
Therefore, total distance travelled by B when it crosses C = 9×\(\frac{4}{7} \) = 5.14 km