Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Let the percentage of 8X16 be ‘a’ and that of 8X18 be ‘100-a’.
As per the given data,
16.2u = {16 (a /100)}+ [18 {(100-a) /100}]
1620 = 16a + 1800 – 18a
1620 = 1800 – 2a
a = 90%
Hence, the percentage of isotope in the sample 8X16 is 90% and that of 8X18 = 100-a = 100- 90=10%