Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Given, distance covered by the truck (s) = 400 meters
Time taken to cover the distance (t) = 20 seconds
Initial velocity of the truck (u) = 0
{since it starts from rest}
We know that, \( s = ut + \frac{1}{2} at^2 \)
\(\therefore \) \( 400 = 0 × 20 + \frac{1}{2} (a)(400) \ = \ 2 m/s^2 \)
Now, force = mass × acceleration
\(\therefore \) force acting on truck = 7000 × 2 = 14000 N