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Answer :
Given, mass of the bullet (m) = 10 g = 0.01 kg
Initial velocity of the bullet (u) = 150 m/s
Terminal velocity of the bullet (v) = 0 m/s
Time period (t) = 0.03 s
We know that, \( v = u +at \)
\(\Rightarrow 0 = 150 + a(0.01) \)
\(\Rightarrow a = - 5000 \ m/s^2 \)
Now, \( v^2 - u ^2 = 2 as \)
\(\Rightarrow 0^2 - 150^2 = 2 × (-5000) s \)
\(\Rightarrow s = 2.25 \ m \)
Now, force exerted by wooden block on bullet = mass of bullet × acceleration of bullet
\( \Rightarrow F = 0.01 × (-5000) = -50 N \)