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# How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be $$10 m/s^2$$.

Given, mass of the dumb-bell (m) = 10 kg

Distance covered (s) = 80 cm = 0.8 m

Initial velocity (u) = 0

Acceleration (a) = $$10 m/s^2$$

Momentum of the dumb-bell when it hits the ground = m v

We know that, $$v^2 - u^2 = 2 a s \$$
$$\Rightarrow \ v^2 - 0 = 2(10)(0.8) \$$
$$\Rightarrow \ v = 4$$

The momentum transferred by the dumb-bell to the floor = (10) × (4) = 40 kg m/s