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Answer :
Given, mass of the dumb-bell (m) = 10 kg
Distance covered (s) = 80 cm = 0.8 m
Initial velocity (u) = 0
Acceleration (a) = \( 10 m/s^2 \)
Momentum of the dumb-bell when it hits the ground = m v
We know that, \( v^2 - u^2 = 2 a s \ \)
\( \Rightarrow \ v^2 - 0 = 2(10)(0.8) \ \)
\( \Rightarrow
\ v = 4 \)
The momentum transferred by the dumb-bell to the floor = (10) × (4) = 40 kg m/s