The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and graphically.

Ans.Let the cost of cricket bat and cricket ball be Rs.x and Rs.y respectively.

According to the given statement in the question:

=>\(3x + 6y = 3900\)
=>\(x + 2y = 1300\)............(i)

Two solutions of the equation (i) are :

\(\begin{array} {|r|r|}\hline 0 & 1300 \\ \hline 650 & 0 \\ \hline \end{array}\)

And also according to the given statement in the question:

=>\(x + 3y = 1300\)............(ii)
Two solutions of the equation (i) are :

\(\begin{array} {|r|r|}\hline 0 & 1300 \\ \hline {{1300} \over {3}} & 0 \\ \hline \end{array}\)

Now the graph for the above equations (i) and (ii) will be: