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The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and graphically.


Answer :

Ans.Let the cost of cricket bat and cricket ball be Rs.x and Rs.y respectively.

According to the given statement in the question:

=>\(3x + 6y = 3900\)
=>\(x + 2y = 1300\)............(i)

Two solutions of the equation (i) are :

\(\begin{array} {|r|r|}\hline 0 & 1300 \\ \hline 650 & 0 \\ \hline \end{array}\)

And also according to the given statement in the question:

=>\(x + 3y = 1300\)............(ii)
Two solutions of the equation (i) are :

\(\begin{array} {|r|r|}\hline 0 & 1300 \\ \hline {{1300} \over {3}} & 0 \\ \hline \end{array}\)

Now the graph for the above equations (i) and (ii) will be:

Graph 2

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