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# A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground?

Given, u = 0 m/s

$$h = s = 19.6 m$$

g = 9.8 m/s2 (falling down)

We know that, $$v^2 – u^2 = 2 g s$$

$$\Rightarrow v^2 – (0)^2 = 2 x 9.8 x 19.6$$

$$\Rightarrow$$ v = 19.6 m/s

The final velocity just before touching the ground is 19.6 m/s.