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Answer :
Given data:
Mass of the sun ms = 2 × 1030 kg
Mass of the earth me = 6 × 1024 kg
Gravitation constant G = 6.67 x 10-11 N m2/ kg2
Average distance r = 1.5 × 1011 m
From Universal law of Gravitation
\( F = \frac{Gm_1 m_2 }{d^2} \ \)
\( \Rightarrow \ F = \frac{ 6.67 × 10^{-11} × 6 × 10^{24} × 2 × 10^{30} }{(1.5 × 10^{11})^2 } \ \)
\( \Rightarrow \ F =3.56 × 10^{23} N \)