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Answer :

p>Consider the length of aluminium rod = d

Speed of sound wave at 25° C in aluminium, \(V_{Al} = 6420 m/s \)

Time taken to reach other end

\( T_Al = \frac{d}{V_{Al} }= \frac{d}{6420} \)

Speed of sound in air, \( V_{air} = 346 m/s \)

Time taken by sound to each other end,

\( T_{air} = \frac{d}{V_{air} } = \frac{d}{346} \)

\(\therefore \) the ratio of time taken by sound in aluminium and air,

= \( \frac{T_{air}}{t_{Al}} = \frac{6420}{346} = 18.55 \)

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