A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, \( g = 10 m/s^2 \) and speed of sound = 340 m/s.

Height (s) of tower = 500 m

Velocity (v) of sound = 340 m/s

Acceleration (g) due to gravity = 10 m/s

Initial velocity (u) of the stone = 0

Time \( t_1 \) taken by the stone to fall to tower base

We know that, \( s= ut_1 + (½) g (t_1)^2 \)

\( \Rightarrow 500 = 0 x t_1 + (½) 10 (t_1)^2 \)

\(\Rightarrow (t_1)^2 = 100 \)

\( \Rightarrow t_1 = 10 s \)

Time \(t_2\) taken by sound to reach top from tower base =\( \frac{500}{340} = 1.47 \ s \) .

\( \therefore t = t_1 + t_2 \)

\(\Rightarrow t = 10 + 1.47 \)

\( \Rightarrow t = 11.47 \ s \).