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Answer :
Height (s) of tower = 500 m
Velocity (v) of sound = 340 m/s
Acceleration (g) due to gravity = 10 m/s
Initial velocity (u) of the stone = 0
Time \( t_1 \) taken by the stone to fall to tower base
We know that, \( s= ut_1 + (½) g (t_1)^2 \)
\( \Rightarrow 500 = 0 x t_1 + (½) 10 (t_1)^2 \)
\(\Rightarrow (t_1)^2 = 100 \)
\( \Rightarrow t_1 = 10 s \)
Time \(t_2\) taken by sound to reach top from tower base =\( \frac{500}{340} = 1.47 \ s \) .
\( \therefore t = t_1 + t_2 \)
\(\Rightarrow t = 10 + 1.47 \)
\( \Rightarrow t = 11.47 \ s \).