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Answer :
Time (t) taken to hear the echo = 5 s
Distance (d) of object from submarine = 3625 m
Total distance travelled by SONAR during reception and transmission in water = 2d
Velocity (v) of sound in water = \( \frac{2d}{t} = \frac{2 × 3625}{5} \)
\( \Rightarrow v = 1450 \ m/s \)