Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?


Answer :

Given, The mass of the body = 1500 kg

Velocity v = 60 km/hr

\( =\frac{60 × 1000}{3600} \ \)

\( = \ \frac{50}{3} \)

The work required to stop the car = kinetic energy change of the car

\( \Rightarrow \ \frac{mv^2}{2} \ - \ \frac{m(0)^2}{2} \ \)

\(\Rightarrow \frac{1500}{ ( \frac{50}{3} )^2} - 2 = 208333.3 J \)

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