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Answer :
In \(\triangle{AOD}\) and \(\triangle{BOC}\), we have,
Now, \(\angle{AOD}\) = \(\angle{BOC}\) ...(vertically opposite angles)
Also, \(\angle{DAO}\) = \(\angle{CBO}\) = \(90^\circ\)
and BD = BC ...(shown in the figure)
Therefore, \(\triangle{AOD}\) \(\displaystyle \cong \) \(\triangle{BOC}\) ...(SAS congruency test)
Hence, OA = OB ...(By CPCT)
Thus, we can say that, O is the mid-point of AB.
So, CD bisects AB.
Hence, proved