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Answer :
Given,
AD is median of \(\triangle \) ABC.
\(\therefore \) it will divide \(\triangle \)ABC into two triangles of equal area.
\(\therefore \) ar(ABD) = ar(ACD) .....(i)
also,
ED is the median of \(\triangle \)ABC.
\(\therefore \) ar(EBD) = ar(ECD) — (ii)
Subtracting (ii) from (i),
ar(ABD) – ar(EBD) = ar(ACD) – ar(ECD)
\(\Rightarrow \) ar(ABE) = ar(ACE)