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Answer :
i) \(\triangle{ACB}\) and \(\triangle{ACF}\) lie on the same base AC and are between
The same parallels AC and BF.
\(\therefore \) Area (\(\triangle{ACB}\)) = Area (\(\triangle{ACF}\))
ii) \(\because \) it can be observed that
Area (\(\triangle{ACB}\)) = Area (\(\triangle{ACF}\))
Now adding Area (ACDE) on both side,
\(\Rightarrow \) Area (\(\triangle{ACB}\)) + Area (ACDE) = Area (\(\triangle{ACF}\)) + Area (ACDE)
\(\Rightarrow \) Area (ABCDE) = Area (AEDF)
Hence, proved.