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# ABC and ADC are two right angled triangles with common hypotenuse AC. Prove that $$\angle{CAD}$$ = $$\angle{CBD}$$.

Draw a circle with AC as diameter passing through B and D. Join BD.

$$\triangle{ADC}$$ and $$\triangle{ABC}$$ are right angled triangles with common hypotenuse.

$$\angle{CBD}$$ = $$\angle{CAD}$$
(Since, angles in the same segment are equal)

Hence, proved.