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Construct a \(\triangle{ABC}\) in which BC = 7 cm, \(\angle{B}\) = \(75^\circ\) and AB + AC = 13cm.
Answer :
Given: In \(\triangle{ABC}\) in which BC = 7 cm, \(\angle{B}\) = \(75^\circ\) and AB + AC = 13cm.
Steps of construction: 
1. Draw the base BC = 7 cm.
2. At the point B make an \(\angle{XBC}\) = \(75^\circ\).
3. Cut a line segment BD equal to AB + AC = 13 cm from the ray BX.
4. Join DC.
5. Make \(\angle{DCY}\) = \(\angle{BDC}\).
6. Let CY intersect BX at A.
Hence, ABC is the required triangle.