Construct right triangles whose base is 12 cm and sum its hypotenuse and other side is 18 cm.

Given: In \(\triangle{ABC}\), base BC = 12 cm, \(\angle{B}\) = \(90^\circ\) and AB + BC = 18 cm.

Steps of construction:



1. Draw the base BC =12cm.

2. At the point B, make an \(\angle{XBC}\) = \(90^\circ\).

3. Cut a line segment BD = AB + AC = 18 cm from the ray BX.

4. Join DC.

5. Draw the perpendicular bisector PQ of CD to intersect BD at a point A.

6. Join AC.
Then, \(\triangle{ABC}\) is the required right triangle.