Q7. Express $$sin 67° + cos 75°$$ in terms of trigonometric ratios of angles between 0° and 45°.

Given,

$$sin 67° + cos 75°$$

= $$sin (90° – 23) + cos (90° – 15°)$$

$$= \ cos 23° + sin 15°$$    [ ∵ $$sin( 90° - \theta) \ = \ cos \theta$$ and $$cos( 90° - \theta) \ = \ sin \theta$$