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Q7. Express \( sin 67° + cos 75° \) in terms of trigonometric ratios of angles between 0° and 45°.
Answer :


Given,

\( sin 67° + cos 75° \)

= \( sin (90° – 23) + cos (90° – 15°) \)

\( = \ cos 23° + sin 15° \)    [ ∵ \( sin( 90° - \theta) \ = \ cos \theta \) and \( cos( 90° - \theta) \ = \ sin \theta \)