For part I :
It is a triangle with sides 5 cm, 5 cm and 1 cm.
Thus, We know that,
Now, Area of part I triangle
(Since, Heron's formula [area =
For part II :
It is a rectangle with sides 6.5 cm and 1 cm
(Since, Area of rectangle = Lenght × Breadth)
For part III :
It is a trapezium ABCD.
(Since, Area of triangle =
Now, Area of trapezium
= 3 × 0.433
Therefore, Area of part III is 1.299
For part IV & V :
Both the parts IV and V are the same.
Area of part IV & V =
So, we get,
Total area of paper used = Area of (I + II + III + IV + V)
= (2.487 + 6.5 + 1.299 + 4.5 + 4.5)