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Answer :
Given :
Length (l) of room = 5 m
Breadth (b) of room = 4 m
Height (h) of room = 3 m
It can be observed that four walls and the ceiling of the room are to be white- washed. The floor of the room is not to be white-washed.
So, we get,
Area to be white-washed
= Area of walls + Area of ceiling of room
= 2lh + 2bh + lb
= [2 x 5 x 3 + 2 x 4 x 3 + 5 x 4] \({m}^2\)
= [30 + 24 + 20] \({m}^2\)
= 74 \({m}^2\).
Now, we have,
Cost of white-washing per \({m}^2\) area = Rs. 7.50
Cost of white-washing 74 \({m}^2\) area = Rs. (74 x 7.50) = Rs. 555
Therefore, the cost of white washing the walls of the room and the ceiling is Rs. 555.