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Answer :

Given :

Length (l) of room = 5 m

Breadth (b) of room = 4 m

Height (h) of room = 3 m

It can be observed that four walls and the ceiling of the room are to be white- washed. The floor of the room is not to be white-washed.

So, we get,

Area to be white-washed

= Area of walls + Area of ceiling of room

= 2lh + 2bh + lb

= [2 x 5 x 3 + 2 x 4 x 3 + 5 x 4] \({m}^2\)

= [30 + 24 + 20] \({m}^2\)

= 74 \({m}^2\).

Now, we have,

Cost of white-washing per \({m}^2\) area = Rs. 7.50

Cost of white-washing 74 \({m}^2\) area = Rs. (74 x 7.50) = Rs. 555

Therefore, the cost of white washing the walls of the room and the ceiling is Rs. 555.

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