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i) What is the area of the glass?

ii) How much of tape is needed for all the 12 edges?

Answer :

Given :

Length (l) of greenhouse = 30 cm

Breadth (b) of greenhouse = 25 cm

Height (h) of greenhouse = 25 cm

We know that,

Total surface area of greenhouse

=2 [lb + lh + bh]

= [2 (30 x 25 + 30 x 25 + 25 x 25)] \({cm}^2\)

= [2(750 + 750 + 625)] \({cm}^2\)

= [2 x 2125] \({cm}^2\)

= 4250 \({cm}^2\)

Therefore, the area of glass is 4250 \({cm}^2\).

It can be observed that tape is required alongside AD, OC, CD, DA, EF, FG, GH, HE, AH, BE, DG, and CF.

We have, Total length of tape

= 4(l+ b + h)

= [4(30 + 25 + 25)] cm

= 320 cm

Therefore, 320 cm tape is required for all the 12 edges.

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