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Answer :
Given :
Length (l) of greenhouse = 30 cm
Breadth (b) of greenhouse = 25 cm
Height (h) of greenhouse = 25 cm
We know that,
Total surface area of greenhouse
=2 [lb + lh + bh]
= [2 (30 x 25 + 30 x 25 + 25 x 25)] \({cm}^2\)
= [2(750 + 750 + 625)] \({cm}^2\)
= [2 x 2125] \({cm}^2\)
= 4250 \({cm}^2\)
Therefore, the area of glass is 4250 \({cm}^2\).
It can be observed that tape is required alongside AD, OC, CD, DA, EF, FG, GH, HE, AH, BE, DG, and CF.
We have, Total length of tape
= 4(l+ b + h)
= [4(30 + 25 + 25)] cm
= 320 cm
Therefore, 320 cm tape is required for all the 12 edges.