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Answer :
Given:
Length (l) of shelter = 4 m
Breadth (b) of shelter = 3 m
Height (h) of shelter = 2.5 m
Tarpaulin will be required for the top and four wall sides of the shelter.
So, Area of Tarpaulin required
= 2(lh + bh) + lb
= [2(4 x 2.5 + 3 x 2.5) + 4 x 3] \({m}^2\)
= [2(10 + 7.5) + 12] \({m}^2\)
= 47 \({m}^2\)
Therefore, 47 \({m}^2\) tarpaulin will be required.