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# The curved surface area of a right circular cylinder of height 14 cm is 88 $${cm}^2$$. Find the diameter of the base of the cylinder.

Given :
Height (h) of cylinder = 14 cm
Curved surface area of cylinder = 88 $${cm}^2$$

Let the diameter of the cylinder be d.
So, ($$2{\pi}rh$$) $${cm}^2$$= 88 $${cm}^2$$
(where, r is the radius of the base of the cylinder)

$$\Rightarrow$$$${\pi}dh$$ = 88 $${cm}^2$$ ...(Since, d = 2r)
$$\Rightarrow$$ d = $$\frac{88 × 7}{22 × 14}$$ cm ...($${\pi} = \frac{22}{7}$$)
$$\Rightarrow$$ d = $$\frac{4}{2}$$ cm
$$\Rightarrow$$ d = 2 cm.

Therefore, the diameter of the base of the cylinder is 2 cm.