The curved surface area of a right circular cylinder of height 14 cm is 88 \({cm}^2\). Find the diameter of the base of the cylinder.

Given :
Height (h) of cylinder = 14 cm
Curved surface area of cylinder = 88 \({cm}^2\)

Let the diameter of the cylinder be d.
So, (\(2{\pi}rh\)) \({cm}^2\)= 88 \({cm}^2\)
(where, r is the radius of the base of the cylinder)

\(\Rightarrow \)\({\pi}dh\) = 88 \({cm}^2\) ...(Since, d = 2r)
\(\Rightarrow \) d = \(\frac{88 × 7}{22 × 14}\) cm ...(\({\pi} = \frac{22}{7} \))
\(\Rightarrow \) d = \(\frac{4}{2}\) cm
\(\Rightarrow \) d = 2 cm.

Therefore, the diameter of the base of the cylinder is 2 cm.