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Answer :
Given :
Height (h) of cylindrical roller = Length of roller = 120 cm
And radius (r) of the circular end roller = \(\frac{84}{2}\) = 42 cm
It can be observed that a roller is cylindrical.
Now, we know that,
CSA of rollar
= \(2{\pi}rh\)
= \(2 × \frac{22}{7} × 42 × 120\) \({cm}^2\)
= \(2 × 22 × 6 × 120\)
= 31680 \({cm}^2\)
Therefore, Area of field
= 500 x CSA of roller
= \(31680 × 500\) \({cm}^2\)
= 1584 \({m}^2\)
\(\therefore\) the area of the playground in \({m}^2\) is 1584.