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Answer :
Given :
Height (h) cylindrical pillar = 3.5 m
Radius (r) of the circular end of pillar = \(\frac{50}{2}\) cm = 25 cm = 0.25m
Now, we know that,
CSA of cylindrical pillar = \(2{\pi}rh\)
= \(2 × \frac{22}{7} × 0.25 × 3.5\) \({m}^2\)
= \(44 × 0.125\) \({m}^2\)
= 5.5 \({m}^2\)
Now, Cost of painting 1 \({m}^2\) area = Rs. 12.50
Cost of painting 5.5 \({m}^2\) area = Rs. (5.5 x 12.50) = Rs. 68.75
Therefore, the cost of painting the CSA of the pillar is Rs. 68.75