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Answer :

Given :

Radius (r) of the base of cylinder = 0.7 m

CSA Of cylinder = 4.4 \({m}^2\)

Let the height of the circular cylinder be h.

Therefore, we have,

\(\Rightarrow \) \(2{\pi}rh\) = 4.4 \({m}^2\)

\(\Rightarrow \) \(2 × \frac{22}{7} × 0.7 × h\) m = 4.4 \({m}^2\)

\(\Rightarrow \) \(2 × 22 × 0.1 × h\) m = 4.4 \({m}^2\)

\(\Rightarrow \) h = 1 m.

Therefore, the height of the cylinder is 1 m.

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