Curved surface area of a right circular cylinder is 4.4 \({m}^2\). If the radius of the base of the cylinder is 0.7 m, find its height.

Given :
Radius (r) of the base of cylinder = 0.7 m
CSA Of cylinder = 4.4 \({m}^2\)

Let the height of the circular cylinder be h.

Therefore, we have,

\(\Rightarrow \) \(2{\pi}rh\) = 4.4 \({m}^2\)
\(\Rightarrow \) \(2 × \frac{22}{7} × 0.7 × h\) m = 4.4 \({m}^2\)
\(\Rightarrow \) \(2 × 22 × 0.1 × h\) m = 4.4 \({m}^2\)
\(\Rightarrow \) h = 1 m.

Therefore, the height of the cylinder is 1 m.