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Answer :
Given :
Radius (r) of the base of cylinder = 0.7 m
CSA Of cylinder = 4.4 \({m}^2\)
Let the height of the circular cylinder be h.
Therefore, we have,
\(\Rightarrow \) \(2{\pi}rh\) = 4.4 \({m}^2\)
\(\Rightarrow \) \(2 × \frac{22}{7} × 0.7 × h\) m = 4.4 \({m}^2\)
\(\Rightarrow \) \(2 × 22 × 0.1 × h\) m = 4.4 \({m}^2\)
\(\Rightarrow \) h = 1 m.
Therefore, the height of the cylinder is 1 m.