Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
In \( ∆ \ ABC \) , \( \frac{AB}{AC} \ = \ sin30º \)
=> \( \frac{AB}{20} \ = \ \frac{1}{2} \) [ \( \because sin30º \ = \ \frac{1}{2} \) ]
=> \( AB \ = \ \frac{1}{2} \ × \ 20 \ = \ 10 \)
\(\therefore \) Height of the pole is 10 m.