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Answer :

Given :

Radius (r) of the base of cone = \(\frac{24}{2} cm = 12 cm\)

Slant height (l) of cone = 21 cm

We know that, TSA of cone

= \({\pi}r(r + l)\)

= [\(\frac{22}{7} × 12 × (12 + 21)\) \({m}^2\)]

= [\(22 × 1.71 × 33\) \({m}^2\)

= 1244.57 \({m}^2\)

Therefore, the total surface area of the cone is 1244.57 \({m}^2\).

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