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Answer :
i) Let ABC be a conical tent.
Given :
Height (h) of conical tent = 10 m
Radius (r) of conical tent = 24 m
Let the slant height of the tent be l.
In \(\triangle{ABO}\),
\(\Rightarrow \) \({AB}^2 = {AO}^2 + {BO}^2\)
\(\Rightarrow \) \({l}^2 = {h}^2 + {r}^2\)
\(\Rightarrow \) \(l^2= {10}^2 + {24}^2 {m}^2\)
\(\Rightarrow \) \(l^2= 676 {m}^2\)
\(\Rightarrow \) \({l}^2 = {26}^2 m\)
\(\Rightarrow \) l = 26 m
Therefore, the slant height Of the tent is 26 m.
ii) We know, CSA of tent
= \({\pi}rl\)
= [\(\frac{22}{7} × 24 × 26 m\)]
= \(\frac{13728}{7} {m}^2\)
Cost of 1 \({m}^2\) canvas = Rs. 70
Cost of [\(\frac{13728}{7} {m}^2\)] canvas
= Rs. [\(\frac{13728}{7} × 70\) \({m}^2\)]
= Rs. 137280.
Therefore, the cost of the canvas required to make such a tent is Rs. 137280.