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# A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

Given :
Radius (r) of conical cap = 7 cm
Height (h) of conical cap = 24 cm

Slant height (l) of the conical cap
$$\Rightarrow$$ $${l}^2 = {h}^2 + {r}^2$$
$$\Rightarrow$$ $$l^2= {7}^2 + {24}^2$$ $${cm}^2$$
$$\Rightarrow$$ $$l^2= 625$$ $${cm}^2$$
$$\Rightarrow$$ $${l}^2 = {25}^2 cm$$
$$\Rightarrow$$ l = 25 cm

Therefore, the slant height Of the tent is 25 cm.

We know, CSA of tent
= $${\pi}rl$$
= [$$\frac{22}{7} × 7 × 25$$ $${cm}^2$$]
= [$$22 × 1 × 25$$ $${cm}^2$$]
= $$550$$ $${cm}^2$$

Thus, CSA of 10 such caps
= (10 x 550) $${cm}^2$$
= 5500 $${cm}^2$$

$$\therefore$$ 5500 $${cm}^2$$ sheet will be required.