A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Given :
Inner radius Of hemispherical bowl = 5cm
Thickness of the bowl = 0.25 cm
Outer radius (r) Of hemispherical bowl = (5 + 0.25) cm = 5.25 cm

We also know that,
Outer CSA of hemispherical bowl
= \(2 {\pi} {r}^2\)
= \(2 × \frac{22}{7} × {5.25}^2\)
= \(173.25 {cm}^2\)

Therefore, the outer curved surface area Of the bowl is 173.25 \({cm}^{2}\)