A cuboidal vessel is 10 m long and 8 m wide. How high must it be made to hold 380 \(m^3\) of a liquid?

Given :
Length (l) of vessel = 10 m
Width (b) Of vessel = 8 m

We know that,

Volume of tank = l x b x h
But, Volume of vessel = 380 \({m}^{3}\)
\(\therefore \) l x b x h = 380 \({m}^{3}\)
\(\Rightarrow\) (10 x 8 x h) \({m}^{2}\) = 380 \({m}^{3}\)
\(\Rightarrow\) (80 x h) \({m}^{2}\) = 380 \({m}^{3}\)
\(\Rightarrow \) h = \(\frac{380}{80}\) m
\(\Rightarrow \) h = 4.75 m

Therefore, the height Of the vessel should be 4.75 m.