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Answer :

Given :

Inner radius of cylindrical pipe (r) = \(\frac{24}{2} cm\) = 12 cm

Outer radius of cylindrical pipe (R) = \(\frac{28}{2} cm\) = 14 cm

Height (h) of pipe = Length of pipe = 35 cm

We know that,

Volume of pipe

= \({\pi}({R}^2 - {r}^2)h\)

= \(\frac{22}{7} × ({14}^2 - {12}^2) × 35\) \({cm}^{3}\)

= 110 x 52 \({cm}^{3}\)

= 5720 \({cm}^{3}\)

Now, Mass of 1 \({cm}^{3}\) wood = 0.6 g

So, Mass of 5720 \({cm}^{3}\) wood br> = (5720 x 0.6) g

= 3432 g

= 3.432 kg

Therefore, mass of the pipe is 3.432 kg.

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