If the lateral surface of a cylinder is 94.2 \({cm}^{2}\) and its height is 5 cm, then and
i) radius of its base
ii) its volume.
(Use \({\pi}\) = 3.14)

i) Given :
Height (h) of cylinder = 5 cm

Let radius of cylinder be r.
Also, CSA of cylinder = 94.2 \({cm}^{2}\)

Thus, we get that,

\(\Rightarrow \) \(2 {\pi} r h\) = 94.2 \({cm}^{2}\)
\(\Rightarrow \) (2 × 3.14 × r × 5) cm = 94.2 \({cm}^{2}\)
\(\Rightarrow \) r = 3 cm

ii) We know that,

Volume of cylinder
= \({\pi} {r}^2 h\)
= \(3.14 × {3}^2 × 5\) \({cm}^{3}\)
= 141.3 \({cm}^{3}\).