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Answer :
Given :
Radius (r) of cylindrical bowl = \(\frac{7}{2} cm = 3.5 cm\)
Height (h) of bowl, up to which bowl is filled with soup = 4 cm
We know that,
Volume Of soup in bowl
= \({\pi} {r}^2 h\)
= \(\frac{22}{7} × {3.5}^2 × 4\) \({cm}^3\)
= 11 × 3.5 × 4 \({cm}^3\)
= 154 \({cm}^3\)
Therefore, Volume of soup given to 250 patients
= (250 × 154) \({cm}^3\)
= 38500 \({cm}^3\)