A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?

Given :
Radius (r) of cylindrical bowl = \(\frac{7}{2} cm = 3.5 cm\)
Height (h) of bowl, up to which bowl is filled with soup = 4 cm

We know that,

Volume Of soup in bowl
= \({\pi} {r}^2 h\)
= \(\frac{22}{7} × {3.5}^2 × 4\) \({cm}^3\)
= 11 × 3.5 × 4 \({cm}^3\)
= 154 \({cm}^3\)

Therefore, Volume of soup given to 250 patients
= (250 × 154) \({cm}^3\)
= 38500 \({cm}^3\)