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Answer :

Given :

Radius (r) of pit = \(\frac{3.5}{2} m = 1.75 m\)

Height (h) of pit = depth of pit = 12 m

We know that,

Volume of pit

= \(\frac{1}{3} {\pi} {r}^2 h\)

= \(\frac{1}{3} × \frac{22}{7} × {3.5}^2 × 12\) \({m}^3\)

= 38.5 \({m}^3\)

Thus, capacity of the pit

= (38.5 × 1) kilolitres

= 38.5 kilolitres

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