A conical pit of top diameter 3.5 m is 12 m deep. What is its capacity in kilolitres?

Given :
Radius (r) of pit = \(\frac{3.5}{2} m = 1.75 m\)
Height (h) of pit = depth of pit = 12 m

We know that,

Volume of pit
= \(\frac{1}{3} {\pi} {r}^2 h\)
= \(\frac{1}{3} × \frac{22}{7} × {3.5}^2 × 12\) \({m}^3\)
= 38.5 \({m}^3\)

Thus, capacity of the pit
= (38.5 × 1) kilolitres
= 38.5 kilolitres